Their distance is the hypotenuse of a triangle with sides 5t and t which will be root((5t)2 + t2). So the distance at time t of the ex lovers will be root(26) × t. You can basically grasp intuitively that the speed is indeed constant and equals to the root(26)=5.1 ft/sec. Technically you’d use the derivative power rule to drop the t and get the speed.
Differential calculus? That looks more like algebra. Their speed is constant.
I agree, it is not calculus, it’s trigonometry.
Each of their speeds is constant, but different, and they’re walking in different directions.
Their distance is the hypotenuse of a triangle with sides 5t and t which will be root((5t)2 + t2). So the distance at time t of the ex lovers will be root(26) × t. You can basically grasp intuitively that the speed is indeed constant and equals to the root(26)=5.1 ft/sec. Technically you’d use the derivative power rule to drop the t and get the speed.